mindstormsguy
Well-Known Member
Everyone who is pointing out the gallons per minute fuel filling analogy is missing a key point. Batteries are not tanks of liquid. With gasoline, the pump at the station is basically what sets your refueling rate. That’s not how EVSE and battery technology works though. With batteries, all else being equal, the charge speed should be proportional to the size of the battery. It’s called “C rate”.
It’s common or standard for a battery (of basically any type) to charge at 1C. If a battery is 10Ah, then 1C = 10A, and charging would take 1 hour (or a little longer, because of tapering at the end). If a battery is 100Ah, then 1C = 100A, and charging takes… 1 hour!
So, if an EV is half as efficient as another, but it has a battery twice as large (to get the same range) it doesn’t matter. A battery twice the size should be able to charge twice as fast. Or put another way, if two EVs have the same charge rate in terms of C, then they’ll have the same charge time. Regardless of the size of the pack.
At the individual cell level, all there is is C. The cells don’t care how many volts and amps are delivered to the pack, they care how many C is delivered to them directly.
Unless an EV is maxing out at 1000V and 500A (the CCS limit), it’s not fair IMO to say “well, of course it charges slower, it’s a bigger battery”. The EVSE is not the limiting factor. Nor is the individual cell capability. The limiting factor is the design of the pack/vehicle itself. Either a cell selection that is simply not capable of the same type of individual charging curve, a more conservative design, a voltage limitation because the vehicle uses older transistor technology limiting to 400V, or a bad cooling system.
If you took two Rivian packs, wired them in series, and hooked them up to a single EA EVSE that is capable of 1000V (as most are) you’d add twice as many MPH. Why? Because you’d use the full voltage available from the EVSE, and you’d have twice as much cooling capacity.
It’s common or standard for a battery (of basically any type) to charge at 1C. If a battery is 10Ah, then 1C = 10A, and charging would take 1 hour (or a little longer, because of tapering at the end). If a battery is 100Ah, then 1C = 100A, and charging takes… 1 hour!
So, if an EV is half as efficient as another, but it has a battery twice as large (to get the same range) it doesn’t matter. A battery twice the size should be able to charge twice as fast. Or put another way, if two EVs have the same charge rate in terms of C, then they’ll have the same charge time. Regardless of the size of the pack.
At the individual cell level, all there is is C. The cells don’t care how many volts and amps are delivered to the pack, they care how many C is delivered to them directly.
Unless an EV is maxing out at 1000V and 500A (the CCS limit), it’s not fair IMO to say “well, of course it charges slower, it’s a bigger battery”. The EVSE is not the limiting factor. Nor is the individual cell capability. The limiting factor is the design of the pack/vehicle itself. Either a cell selection that is simply not capable of the same type of individual charging curve, a more conservative design, a voltage limitation because the vehicle uses older transistor technology limiting to 400V, or a bad cooling system.
If you took two Rivian packs, wired them in series, and hooked them up to a single EA EVSE that is capable of 1000V (as most are) you’d add twice as many MPH. Why? Because you’d use the full voltage available from the EVSE, and you’d have twice as much cooling capacity.
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